8x^2+74x+18=0

Solution for 8x^2+74x+18=0 equation:

8x^2+74x+18=0

a = 8; b = 74; c = +18;
Δ = b2-4ac
Δ = 742-4·8·18
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4900}=70$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(74)-70}{2*8}=\frac{-144}{16}
=-9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(74)+70}{2*8}=\frac{-4}{16}
=-1/4
$